Let . Then according to the definition of derivative

(Your answer above and the next few answers below will involve the variables and .)
The expression inside the limit simplifies to a simple fraction with
numerator
and denominator
We can cancel the factor appearing in the denominator against a similar factor appearing in the numerator leaving a simpler fraction with
numerator
and denominator
Taking the limit of this fractional expression gives us

You can earn partial credit on this problem.