Let \mathbf a = \langle 2, 3 \rangle and
\mathbf b = \langle 1, -2 \rangle .
Show that there are scalars s and t so that
s \mathbf a + t \mathbf b = \langle 1, -9 \rangle

You might want to sketch the vectors to get some intuition.

s =

t =

You might want to sketch the vectors to get some intuition.

You can earn partial credit on this problem.