Let $f(x) = \begin{cases} \sqrt{-3-x}+1, &\text{if}\ x< -4\\ 1, &\text{if}\ x=-4\\ 2 x+10, &\text{if}\ x> -4 \end{cases}$

Calculate the following limits. Enter DNE if the limit does not exist.

$\displaystyle{\lim_{x\to -4^-}f(x)=}$

$\displaystyle{\lim_{x\to -4^+}f(x)=}$

$\displaystyle{\lim_{x\to -4}f(x)=}$