Let $f(x) =\sqrt{38-x}$
The slope of the tangent line to the graph of $f(x)$ at the point $(2,6)$ is .
The equation of the tangent line to the graph of $f(x)$ at $(2,6)$ is $y=mx+b$ for
$m=$
and
$b=$.
Hint: the slope at $x=2$ is given by
$\displaystyle{ m= \lim_{h \to 0}\frac{f(2+h)-f(2)}{h}}$