Let $f(x) = \begin{cases} {-5}-x^2 & x \leq 0\\ -5 & x > 0 \end{cases} .$

(A) Sketch the graph of $f$, and when you're done, place a "1" in the box:

(B) Find the value of $x$ where $f$ is discontinuous. If there is no value, enter 'NONE'.

$x$-values =

(C) Find the value of $x$ where $f$ is nondifferentiable. If there is no value, enter 'NONE'.

$x$-values =