An aluminum can is to be constructed to contain 1400 $cm^3$ of liquid.
Let $r$ and $h$ be the radius of the base and the height of the can respectively.

a) Express $h$ in terms of $r$. (If needed you can enter $\pi$ as pi.)

$h =$

b) Express the surface area of the can in terms of $r$.

Surface area =

c) Approximate the value of $r$ that will minimize the amount of required material (i.e. the value of $r$ that will minimize the surface area).
What is the corresponding value of $h$?

$r =$
$h =$