The force $F$ on an object is the product of the mass $m$ and the acceleration $a$. In this problem, assume that the mass and acceleration both depend on time $t$, hence so the does the force. That is,

$F(t) = m(t)a(t)$

At time $t=10$ seconds, the mass of an object is $34$ grams and changing at a rate of $2 \frac{g}{s}$. At this same time, the acceleration is $7 \frac{m}{s^2}$ and changing at a rate of $6 \frac{m}{s^3}$.

By the product rule, the force on the object is changing at the rate of

.

Please include units in your answer (click the link for help).. To enter compound units use multiplication, division, and exponent symbols, e.g., use ft*lb for foot-pounds or m/s^2 for meters per second per second.