The pressure, measured in Pascals (abbreviated Pa) on a certain object B is proportional to the temperature measured in degrees Kelvin (degK), and inversely proportional to the volume of B in cubic meters: $$P=\frac{T}{V}\; c$$ where $c$ is a physical constant that depends on B and converts the units to Pascals. In this problem it is $$c = 1 \frac{\text{Pa}*\text{m}^3}{\text{degK}}.$$ Suppose the temperature and the volume both depend on time, hence so the does the pressure: $P(t) = \frac{T(t)}{V(t)} c$. At time $t=10$ seconds the temperature of B is $34 \; \text{degK}$ and is increasing at a rate of $2 \; \frac{\text{degK}}{\text{s}}$, and the volume is $7\; \text{m}^3$ and is increasing at the rate $6\; \frac{\text{m}^3}{\text{s}}$.

Using the quotient rule, the pressure on the object is changing at the rate
Your answer should include units.