A skydiver's velocity $v\ge 0$ satisfies the differential equation $$\frac{dv}{dt}=9.8-c\cdot v^2,$$ where $c>0$ is the (per unit mass) coefficient of friction and $v$ is measured in meters per second.

Part A). In the space below sketch the phase portrait for $v\ge 0$ when $c=2$.

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Part B). Find and classify the positive equilibrium solution.
The positive equilibrium velocity is $v =$ meters per second.
The equilibrium type is a ?? sink source node .