WeBWorK Standalone Renderer

$x$	$f(x)$	$g(x)$
$-3$	$1$	$-3$
$-2$	$-3$	$2$
$-1$	$3$	$-1$
$0$	$5$	$1$
$1$	$0$	$-1$

Use the table defining $f$ and $g$ to solve:
NOTE: Write Does not exist if the value does not exist.

a) $(f - g)(0) =$

b) $(f + g)(0) - (g-f)(-1) =$

c) $\displaystyle \left(\frac{f}{g}\right)(0) =$

You can earn partial credit on this problem.