A spring with a 3-kg mass and a damping constant 12 can be held stretched 0.5 meters beyond its natural length by a force of 2 newtons. Suppose the spring is stretched 1 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value $c^2 - 4mk$? $\text m^2\text{kg}^2/\text{sec}^2$ Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form $c_1 e^{\alpha t} + c_2 e^{\beta t}$ where
$\alpha =$ (the larger of the two)
$\beta =$ (the smaller of the two)
$c_1 =$ $c_2 =$