A spring with a 3-kg mass and a damping constant 4 can be held stretched 0.5 meters beyond its natural length by a force of 2 newtons. Suppose the spring is stretched 1 meters beyond its natural length and then released with zero velocity, In the notation of the text, what is the value $c^2 - 4mk$? $\text m^2\text{kg}^2/\text{sec}^2$ Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t with the general form $c_1 e^{\alpha t}\cos(\beta t) + c_2 e^{\gamma t}\sin(\delta t)$
$\alpha =$
$\beta =$
$\gamma =$
$\delta =$
$c_1 =$
$c_2 =$