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 The figure shows an interactive graph of $y = f(t)$. (It may take a minute to load -- be patient.) You can change the value of $x$ in the graph by clicking and dragging the red dot along the horizontal $t$-axis. Assume that the lines in each piece of $f$ continue beyond the graphing window. Define a function that accumulates signed area between the $t$-axis and the graph of $y = f(t)$ by $\displaystyle F(x) = \int_0^x f(t) \, dt$ (a) For what values of $x$ does $F(x) = 0$? $x \approx$ (b) For what values of $x$ is $F(x) \geq 0$? All $x$ in the interval (c) For what values of $x$ does $F(x) = 6$? $x \approx$ (d) Why is $F(x)$ positive when $x$ is negative? A. Because accumulation functions like $F(x)$ are always positive B. Because integrals are always positive C. Because integrating right-to-left is negative D. Because $f(x)$ is negative and integrating right-to-left is negative E. None of the above Graph of $y = f(t)$

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