View the curve $(y-x)^2 + 2 = xy - 3$ as a contour of $f(x,y)$.

(a) Use $\nabla f (-3,-2)$ to find a vector normal to the curve at $(-3,-2)$.


(b) Use your answer to part (a) to find an implicit equation for the tangent line to the curve at $(-3,-2)$.