Set up a double integral for calculating the flux of $\vec{F} = 2 x \vec{i} + y \vec{j} + z \vec{k}$ through the part of the surface $z = -4 x - 2 y + 5$ above the triangle in the xy-plane with vertices $(0,0)$, $(0,3)$, and $(3,0)$, oriented upward.

Instructions: Please enter the integrand in the first answer box. Depending on the order of integration you choose, enter dx and dy in either order into the second and third answer boxes with only one dx or dy in each box. Then, enter the limits of integration and evaluate the integral to find the flux.

Flux = $\displaystyle \int_A^B \!\! \int_C^D$

A =
B =
C =
D =

Flux = $\displaystyle \iint\limits_S \vec{F} \cdot d\vec{A}$ =