Find the inverse Laplace transform $f(t) = {\mathcal L}^{-1} \left\lbrace F(s) \right\rbrace$ of the function $\displaystyle F(s) = \frac{e^{-s}\!\left(5-6s\right)}{s^{2}+36}$.
You may use $h(t)$ for the Heaviside step function.

$\displaystyle f(t) = {\mathcal L}^{-1} \left\lbrace \frac{e^{-s}\!\left(5-6s\right)}{s^{2}+36} \right\rbrace =$ help (formulas)