Evaluate the following limit by simplifying the expression (first answer box) and then evaluating the limit (second answer box). $\displaystyle{ \lim_{x\to 0} \ {x\!\left(12+\frac{6}{x}\right)} = \lim_{x\to 0} }$ $\displaystyle{= }$ . Note: In your written solution, you should write the limit statement $\displaystyle{\lim_{x \to 0}}$ in every step except the last one, where the limit is finally evaluated.