Given $$\left[\begin{array}{cccc} -1 &-1 &-1 &0\cr 1 &2 &3 &1\cr -1 &-1 &-1 &0 \end{array}\right] \sim \left[\begin{array}{cccc} 1 &0 &-1 &-1\cr 0 &1 &2 &1\cr 0 &0 &0 &0 \end{array}\right],$$ use the reduced row echelon form above to solve the system $$\left\lbrace \begin{array}{rcr} -x-y-z & = & 0 \\ x+2y+3z & = & 1 \\ -x-y-z & = & 0 \end{array} \right.$$ If necessary, parametrize your answer using the free variables of the system.

$\left\lbrack \begin{array}{c} x \\ y \\ z \end{array} \right\rbrack =$ $\left[\Rule{0pt}{3.6em}{0pt}\right.$$\left]\Rule{0pt}{3.6em}{0pt}\right.$