Let $$A = \left[\begin{array}{ccccc} 0 &0 &0 &0 &1\cr -3 &1 &3 &0 &2\cr -3 &1 &3 &0 &1\cr 0 &-3 &4 &-3 &-1 \end{array}\right].$$
A basis for the row space of $A$ is $\big\lbrace$ $\big\rbrace.$ vector