WeBWorK Standalone Renderer

Write the vector $\left<-12,0,-5\right>$ as a linear combination of $\vec{a}_1 = \left<-3,1,-3\right>$ , $\vec{a}_2 = \left<3,5,0\right>$ and $\vec{a}_3 = \left<-3,2,-1\right>$ . Express your answer in terms of the named vectors. Your answer should be in the form $4\vec{a}_1 + 5 \vec{a}_2 + 6 \vec{a}_3$ , which would be entered as $\verb!4a1 + 5a2 + 6a3!$ .

$\left<-12,0,-5\right> =$
Represent the vector $\left<-12,0,-5\right>$ in terms of the ordered basis $\mathcal{B} = \lbrace \left<-3,1,-3\right>, \left<3,5,0\right>, \left<-3,2,-1\right> \rbrace$ . Your answer should be a vector of the general form $\verb+<1,2,3>+$ .

$\lbrack \left<-12,0,-5\right> \rbrack_{\mathcal{B}} =$

You can earn partial credit on this problem.