Let $\displaystyle \int_{-6}^{3} f(x) dx =6, \int_{-6}^{-3} f(x) dx=2, \int_{0}^{3} f(x)dx =8$.
Find $\displaystyle \int_{-3}^{0} f(x)dx=$
and $\displaystyle \int_{-3}^{0} (6 f(x)- 2)dx=$