An electric motor converts electricity to rotating shaft work with an efficiency of 27%. The rotating shaft turns the impeller in the pump which, in turn, increases the pressure of the water ($\displaystyle \rho=1000 \frac{\text{kg}}{\text{m}^3}$) by 200 kPa. If the motor is consuming 3.5 kW of electricity, and water flow through the pump is 3.25 $\displaystyle \frac{\text{L}}{\text{s}}$ (at a constant velocity), what is the mechanical efficiency with which the pump converts the rotation of the impeller into water pressure? **Note: You may ignore any changes in potential energy.

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