Consider a triangle with vertices of angle measure $A$, $B$ and $C$ and corresponding opposite sides of length $a$, $b$ and $c$ respectively.

Assuming:

$a=14.500$
$b=8.845$
$\angle B=5.835 ^\circ$

results in two possible triangles. Determine both solutions:

1st Triangle		2nd Triangle
$\angle A_1$ = $\angle C_1$ = $c_1$ =		$\angle A_2$ = $\angle C_2$ = $c_2$ =

Give your answers to at least 3 decimal places.

Hint: