Consider the function $f(x) = \frac{x^{2}-9}{x-3}$.

(a) Fill in the following table of values for $f(x)$:

$x =$	2.9	2.99	2.999	2.9999	3.0001	3.001	3.01	3.1
$f(x) =$

(b) Based on your table of values, what would you expect the limit of $f(x)$ as $x$ approaches 3 to be?
$\lim\limits_{x\to 3}\,\frac{x^{2}-9}{x-3} =$

(c) Graph the function to see if it is consistent with your answers to parts (a) and (b). By graphing, find an interval for $x$ near $3$ such that the difference between your conjectured limit and the value of the function is less than 0.01. In other words, find a window of height 0.02 such that the graph exits the sides of the window and not the top or bottom. What is the window?
$\le x \le$ ,
$\le y \le$ .