WeBWorK Standalone Renderer

Let

$A = \left[ \begin{array}{rrr} 3 & 6 & -13\\ 1 & 3 & -6\\ 1 & 2 & -4 \end{array} \right] \qquad B = \left[ \begin{array}{rrr} 5 & -10 & -19\\ -3 & 5 & 11\\ 1 & -2 & -4 \end{array} \right]$

$C = \left[ \begin{array}{rrrrrr} 3 & 6 & -13 & 0 & 0 & 0\\ 1 & 3 & -6 & 0 & 0 & 0\\ 1 & 2 & -4 & 0 & 0 & 0\\ 0 & 0 & 0 & 5 & -10 & -19\\ 0 & 0 & 0 & -3 & 5 & 11\\ 0 & 0 & 0 & 1 & -2 & -4 \end{array} \right]$

Find the inverses of $A$ , $B$ and $C$ .

$A^{-1}=$

$\left.\vphantom{\begin{array}{c}\!\strut\\\!\strut\\\!\strut\\\!\strut\\\end{array}}\right[$				$\left.\vphantom{\begin{array}{c}\!\strut\\\!\strut\\\!\strut\\\!\strut\\\end{array}}\right]$

$B^{-1}=$

$\left.\vphantom{\begin{array}{c}\!\strut\\\!\strut\\\!\strut\\\!\strut\\\end{array}}\right[$				$\left.\vphantom{\begin{array}{c}\!\strut\\\!\strut\\\!\strut\\\!\strut\\\end{array}}\right]$

$C^{-1}=$

$\left.\vphantom{\begin{array}{c}\!\strut\\\!\strut\\\!\strut\\\!\strut\\\!\strut\\\!\strut\\\!\strut\\\end{array}}\right[$							$\left.\vphantom{\begin{array}{c}\!\strut\\\!\strut\\\!\strut\\\!\strut\\\!\strut\\\!\strut\\\!\strut\\\end{array}}\right]$

You can earn partial credit on this problem.