Use current divider and equivalent resistances to analyze this circuit. In the circuit shown, $I_S = 16 mA$, $R_1 = 15 k\Omega$, $R_2 = 6 k\Omega$, $R_3 = 20 k\Omega$, and $R_4 = 24 k\Omega$.

The equivalent resistance of $R_3$ and $R_4$ = $k\Omega$
The equivalent resistance of $R_2$, $R_3$ and $R_4$ = $k\Omega$
The total resistance seen by the current source = $k\Omega$
The current through $R_1$ is $I_1 =$ $mA$
The current through $R_2$ is $I_2 =$ $mA$