Use nodal analysis to find $V_1$ in the circuit given that $I_1 = 3 mA, I_2 = 5.5 mA, R_1 = 2 k\Omega, R_2 = 13 k\Omega,$ $R_3 = 8 k\Omega$ and $R_4 = 5 k\Omega.$
Note: since there are no voltage sources, the bottom node is chosen as the reference because it has the most number of elements connected to it.
Fill in the values for the two nodal analysis equations using the convention that positive current in an independent current source is defined as entering the node and positive current in the resistor is defined as leaving the node.

The nodal analysis equation at node 1:
$V_1$ + $V_2$ =

The nodal analysis equation at node 2:
$V_1$ + $V_2$ =

Now solve for $V_1 =$ $V$