Using Thevenin's theorem, find $V_o$ in the circuit shown given that $V_s = 8 V$, $R_1 = 9 k\Omega$, $R_2 = 3 k\Omega$, and $R_3 = 12 k\Omega$.

The open-circuit voltage with $R_3$ removed:
$V_{oc} =$ $V$
The short-circuit current with $R_3$ removed and replaced by a short-circuit:
$I_{sc} =$ $mA$
The Thevenin resistance with $R_3$ removed and looking into the $R_3$ terminals:
$R_{th} =$ $k\Omega$
$V_o =$ $V$