Find the approximate value of $f^{-1}(2)$ for the function $f(x) = 0.2 x + 0.6 x^3 + 0.2 x^5$.

$f^{-1}(2) =$ .

Hint: Do not try to find $f^{-1}(x)$ for arbitrary $x$; it's impossible. Use the intersect feature on your calculator or some other technology. Your answer needs to be correct to within one tenth of a percent.