Consider the line with these parametric equations:

$\quad \quad x = -3 t - 6$

$\quad \quad y = 3 t+ 1$

$\quad \quad z = -15 t - 6$ .

One set of symmetric equations for this line is

$$\frac{x + 6}{-3} = \frac{y - y_0}{b} = \frac{z - z_0}{c} ,$$

where $y_0 =$ , $z_0 =$ , $b =$ , and $c =$ .

Another set of symmetric equations for this line is

$$\frac{x}{1} = \frac{y - y_1}{b} = \frac{z - z_1}{c} ,$$

where $y_1 =$ , $z_1 =$ , $b =$ , and $c =$ .