Find the derivative of $f:\mathbb{R}^3\to\mathbb{R}^2$ defined by $f(x,y,z)=(6 x^2 y, e^{6 y - 2 z})$. The derivative $f':\mathbb{R}^3\to\mathbb{R}^{2\times 3}$ is defined by
$f'(x,y,z) =$ $\left[\Rule{0pt}{2.4em}{0pt}\right.$$\left]\Rule{0pt}{2.4em}{0pt}\right.$