Let $h=f\circ g$ where $f:\mathbb{R}^2\to\mathbb{R}$ and $g:\mathbb{R}^2\to\mathbb{R}^2$ is defined by $g(x,y)=(-2x^{2}y,x+2y)$. Find the derivative $h'(2,3)$ if $f_x(-24,8)= -3$ and $f_y(-24,8)= 2$.
$h'(2,3) =$ $\left[\Rule{0pt}{1.2em}{0pt}\right.$$\left]\Rule{0pt}{1.2em}{0pt}\right.$
Find the following:
$h_x(2,3)=$
$h_y(2,3)=$