Determine whether the given proposition is true or false, for the universe of all real numbers. Use T for true and F for false.
$$(\forall x)(\exists y)(x^2+y=0)$$
Answer:
$$(\exists x)(\forall y)(x^2+y=0)$$
Answer:
$$(\exists x)(\exists y)(x^2+y=0)$$
Answer:
$$(\forall y)(\exists x)(y=x^2)$$
Answer:
$$(\forall y)[y\geq 0 \implies (\exists x)(y=x^2)]$$
Answer: