Let $$A=\left[\begin{array}{cccc} -3 &0 &0 &0\cr -4 &-1 &0 &4\cr -14 &10 &-1 &16\cr 2 &-1 &0 &-5 \end{array}\right].$$ Find a matrix $P$ such that $D=P^{-1} A P$ is the Jordan canonical form of $A$. The Jordan form is upper triangular. The blocks are ordered increasingly by eigenvalue and then by block size.
$P =$ $\left[\Rule{0pt}{4.8em}{0pt}\right.$$\left]\Rule{0pt}{4.8em}{0pt}\right.$, $D =$ $\left[\Rule{0pt}{4.8em}{0pt}\right.$$\left]\Rule{0pt}{4.8em}{0pt}\right.$