Let $V={\mathbb R}$. For $u,v \in V$ and $a\in{\mathbb R}$ define vector addition by $u \boxplus v := u+v + 2$ and scalar multiplication by $a \boxdot u := au + 2a - 2$. It can be shown that $(V,\boxplus,\boxdot)$ is a vector space over the scalar field $\mathbb R$. Find the following:

the sum:

$1\boxplus -6 =$

the scalar multiple:

$5\boxdot 1 =$

the zero vector:

$\underline{0}_V =$

the additive inverse of $x$:

$\boxminus x=$