Let $A=$

$\left.\vphantom{\begin{array}{c}\!\strut\\\!\strut\\\!\strut\\\!\strut\\\!\strut\\\end{array}}\right[$ -6 2 -7 6 $\left.\vphantom{\begin{array}{c}\!\strut\\\!\strut\\\!\strut\\\!\strut\\\!\strut\\\end{array}}\right]$ 10 1 -6 5 -2 2 -2 5 6 2 -6 1

Then ${\rm tr}(A^T)=$ and $A^T (1,2)=$ .