Take the function $f(t) = 3 t^{3}(t-2)$ defined on $[0,2]$. Let $F_{\text{odd}}$ and $F_{\text{even}}$ be the odd and the even periodic extensions.

Compute:
$F_{\text{odd}}(0.1) = {}$
$F_{\text{odd}}(-0.5) = {}$
$F_{\text{odd}}(3) = {}$
$F_{\text{odd}}(-3) = {}$
$F_{\text{even}}(0.1) = {}$
$F_{\text{even}}(-0.5) = {}$
$F_{\text{even}}(3) = {}$
$F_{\text{even}}(-3) = {}$

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