Take the function f(t) = 3 t^{3}(t-2) defined on [0,2] .
Let F_{\text{odd}} and F_{\text{even}} be the odd and
the even periodic extensions.

Compute:

F_{\text{odd}}(0.1) = {}

F_{\text{odd}}(-0.5) = {}

F_{\text{odd}}(3) = {}

F_{\text{odd}}(-3) = {}

F_{\text{even}}(0.1) = {}

F_{\text{even}}(-0.5) = {}

F_{\text{even}}(3) = {}

F_{\text{even}}(-3) = {}

help (numbers)

Compute:

help (numbers)

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