To solve this problem let denote the width of the poster in inches and let denote the length in inches. We need to maximize the following function of and : We can reexpress this as the following function of alone: We find that has a critical number at To verify that has a maximum at this critical number we compute the second derivative and find that its value at the critical number is , a negative number. Thus the optimal dimensions of the poster are inches in width and inches in height giving us a maximumal printed area of square inches.
You can earn partial credit on this problem.