Let $h(x) = 5-2x^{3}$,

$h'( 1 ) =$

Use this to find the equation of the tangent line to the curve $y = 5-2x^{3}$ at the point $( 1 , 3 )$ and write your answer in the form:

$y = mx+b$, where $m$ is the slope and $b$ is the y-intercept.