Suppose $f(x) = \frac{2}{x-3}$,

$f'( 4 ) =$

Use this to find the equation of the tangent line to the curve $y = \frac{2}{x-3}$ at the point $( 4 , 2 )$. Write you answer in the form $y = mx + b$, where $m$ is the slope and $b$ is the $y$-intercept

The equation of the tangent line is .