Check that the equation below is not exact but becomes exact when multiplied by the integrating factor.
$$x^2y^3+x(1+y^2)y'=0$$ Integrating factor: $\mu(x,y) = 1/(xy^3)$.

Solve the differential equation. You can define the solution curve implicitly by a function in the form $F(x,y) = G(x) + H(y) =K$ for some constant $K$.

$F(x,y) =$