Using the method of $u$-substitution,

$\displaystyle \int_{3}^{5} (3 x - 6)^{2} \, dx = \int_{a}^{b} f(u) \, du$

where

$u =$ (enter a function of $x$)
$du =$ $dx$ (enter a function of $x$)
$a =$ (enter a number)
$b =$ (enter a number)
$f(u) =$ (enter a function of $u$).

The value of the original integral is .

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