The form of the partial fraction decomposition of a rational function is given below.

$$\frac{x^{2}-2x-60}{(x-2)(x^2+16)} = \frac{A}{x - 2} + \frac{B x + C}{x^2+16}$$
$A =$ $B =$ $C =$

Now evaluate the indefinite integral.

$$\int \frac{x^{2}-2x-60}{(x-2)(x^2+16)} dx$$
Answer = ${} + K$