Find real-valued closed formulas for the trajectory $x(t+1)=Ax(t)$, where $$A= \left[\begin{array}{cc} -15 &18\cr -45 &39 \end{array}\right] \ \mbox{ and } \ \vec{x}(0)=\left[\begin{array}{c} 0\cr 1 \end{array}\right] .$$
$\vec{x}(t)=$ $\left[\Rule{0pt}{2.4em}{0pt}\right.$$\left]\Rule{0pt}{2.4em}{0pt}\right.$