WeBWorK Standalone Renderer

If $A = \left[\begin{array}{cc} -6 &1\cr 1 &-6 \end{array}\right]$ and $Q(\vec{x})= \vec{x}^T A \vec{x},$ then

$Q(\vec{e}_1)=$ ,
$Q(\vec{e}_2)=$ .

You can earn partial credit on this problem.