WeBWorK Standalone Renderer

If $A = \left[\begin{array}{cccc} -3 &1 &0 &0\cr -2 &1 &0 &0\cr 0 &0 &-1 &5\cr 0 &0 &-3 &14 \end{array}\right],$ then

$A^{-1} =$ $\left[\Rule{0pt}{4.8em}{0pt}\right.$ $\left]\Rule{0pt}{4.8em}{0pt}\right.$ .