Weights of 10 red and 36 brown randomly chosen M{\&}M plain candies are listed below.

Red: $\begin{array}{lllll} 0.913& 0.874& 0.908& 0.898& 0.882 \cr 0.891& 0.909& 0.897& 0.92& 0.907 \end{array}$
Brown: $\begin{array}{llllll} 0.923& 0.909& 0.861& 0.875& 1.001& 0.9 \cr 0.985& 0.928& 0.905& 0.929& 0.912& 0.988 \cr 0.902& 0.897& 0.889& 0.909& 0.872& 0.858 \cr 0.914& 0.918& 0.877& 0.92& 0.92& 0.986 \cr 0.904& 0.913& 0.856& 0.871& 0.866& 0.966 \cr 0.857& 0.955& 0.921& 0.936& 0.93& 0.898 \end{array}$
1. $\ $ To construct a 90% confidence interval for the mean weight of red M{\&}M plain candies, you have to use
A. The t distribution with 11 degrees of freedom
B. The normal distribution
C. The t distribution with 9 degrees of freedom
D. The t distribution with 10 degrees of freedom
E. None of the above
2. $\ $ A 90% confidence interval for the mean weight of red M{\&}M plain candies is
$< \mu <$ 3. $\ $ To construct a 90% confidence interval for the mean weight of brown M{\&}M plain candies, you have to use
A. The t distribution with 36 degrees of freedom
B. The t distribution with 35 degrees of freedom
C. The normal distribution
D. The t distribution with 37 degrees of freedom
E. None of the above
4. $\ $ A 90% confidence interval for the mean weight of brown M{\&}M plain candies is
$< \mu <$