For each of the following functions, state whether they are onto or not. (You must enter T or F -- True and False will not work.)

 1. $f: \textbf{R}-\{0\} \longrightarrow \textbf{R}, f(x)=1/x^2$
 2. $f: [-12,0] \longrightarrow [0,144], f(x)=x^2$
 3. $f: \textbf{R}-\{0\} \longrightarrow \textbf{R}-\{0\}, f(x)=1/x^3$
 4. $f: \textbf{R} \longrightarrow \textbf{R}, f(x)=x^3$
 5. $f: (-\infty,-12] \longrightarrow (0,1/144], f(x)=1/x^2$
For each of the following functions, state whether they are onto or not. (You must enter T or F -- True and False will not work.)

 1. $f: (-8,0] \longrightarrow \textbf{R}, f(x)={1 \over {x^2-64}}$
 2. $f: (8,\infty) \longrightarrow (0,\infty), f(x)={1 \over {x^2-64}}$
 3. $f: [0,8) \longrightarrow (-\infty,-1/64], f(x)={1 \over {x^2-64}}$
 4. $f: (8,\infty) \longrightarrow \textbf{R}, f(x)={1 \over {x^2-64}}$
 5. $f: \textbf{R}-\{8,-8\} \longrightarrow (-\infty,-1/64] \cup (0,\infty), f(x)={1 \over {x^2-64}}$
 6. $f: (-8,8) \longrightarrow (-\infty,-1/64], f(x)={1 \over {x^2-64}}$
 7. $f: [0,8) \longrightarrow \textbf{R}, f(x)={1 \over {x^2-64}}$
 8. $f: \textbf{R}-\{8,-8\} \longrightarrow \textbf{R}, f(x)={1 \over {x^2-64}}$
 9. $f: (-\infty,-8) \longrightarrow (0,\infty), f(x)={1 \over {x^2-64}}$
 10. $f: (-8,0] \longrightarrow (-\infty,-1/64], f(x)={1 \over {x^2-64}}$
 11. $f: (-8,8) \longrightarrow \textbf{R}, f(x)={1 \over {x^2-64}}$
 12. $f: (-\infty,-8) \longrightarrow \textbf{R}, f(x)={1 \over {x^2-64}}$