Let $A$ be a $3 \times 2$ matrix with linearly independent columns. Suppose we know that $\vec{u} = \left[\begin{array}{c} -3\cr -3 \end{array}\right]$ and $\vec{v} = \left[\begin{array}{c} 1\cr 3 \end{array}\right]$ satisfy the equations $A\vec{u} = \vec{a}$ and $A\vec{v} = \vec{b}$. Find a solution $\vec{x}$ to $A\vec{x} = 4 \vec{a} - 4 \vec{b}$.

$\vec{x} =$ $\left[\Rule{0pt}{2.4em}{0pt}\right.$$\left]\Rule{0pt}{2.4em}{0pt}\right.$.