If $$A = \left[\begin{array}{cccc} -3 &0 &0 &0\cr 5 &1 &0 &0\cr 1 &2 &-3 &0\cr -5 &-2 &1 &3 \end{array}\right],$$ then
$A^{-1} =$ $\left[\Rule{0pt}{4.8em}{0pt}\right.$$\left]\Rule{0pt}{4.8em}{0pt}\right.$.